Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Lateral Area of a Pyramid

  1. Jun 28, 2005 #1
    This problem is really getting to me, and I don't know why...

    INfo: Pyramid, Side length = 300 ft, perpendicular height = 321 ft, and slant height = (work shown later)

    1. Find the slant height. Round your answer to the nearest whole number.
    (slant height)^2 = (height)^2 + (.5(side))^2
    = (321)^2 + (150)^2
    (slant height)^2 = 125,541
    slant height = 354 feet.

    Is that correct?

    2. Use your previous answer to find the area of the lateral face.
    (I'm not sure if I need to use height or slant height, but I used slant height, because when set straight, the slant height is perpendicular to the base. Please correct me if I'm wrong.)
    area = .5(base)(height)
    = .5(300)(354)
    = 53, 100.

    My main concern here is whether to use the slant height (354) or height (321) and why...

    Thanks for all the help.
    Last edited: Jun 28, 2005
  2. jcsd
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook

Can you offer guidance or do you also need help?
Draft saved Draft deleted