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Launched Rocket

  1. Sep 29, 2012 #1
    1. The problem statement, all variables and given/known data

    a rocket is launched at an angle of 53 degrees above the horizontal with an initial speed of 100 m/s. the rocket moves for 3 s along its initial straight line of motion with an acceleration of 30m/s^2. FInd the max altitude reached by the rocket
    2. Relevant equations

    y=y0 + v0*t +1/2*g*t^(2)

    v0y=v0sin(53)
    v0x=v0cos(53)

    vy=v0y+g*t


    3. The attempt at a solution

    velocity components:

    v0y=100m/s*sin(53)=79.86m/s
    v0x=100m/s*cos(53)=60.18m/s

    Found the vertical distance with the acceleration of 30m/s^(2) for 3sec

    y=y0 + v0*t +1/2*g*t^(2)
    y=79.86m/s*3 sec + 1/2*30m/s*(3sec)^(2) =374.58m

    now I am trying to find my final velocity for the acceleration of 30m/s^(2) for 3sec because that will be my initial velocity for the acceleration of 9.8m/s^(2)

    I use this formula, vy=v0y+gt

    I am not sure which v0y do I use. Do i just use the initial velocity of 100m/s or do I use my v0y that I calculated?(100*sin(53)=79.86m/s) Which one do I use and why? thanks
    1. The problem statement, all variables and given/known data



    2. Relevant equations



    3. The attempt at a solution
     
  2. jcsd
  3. Sep 29, 2012 #2
    a rocket is launched at an angle of 53 degrees above the horizontal with an initial speed of 100 m/s. the rocket moves for 3 s along its initial straight line of motion with an acceleration of 30m/s^2. FInd the max altitude reached by the rocket

    ----------------------------------------
    I guess after 3sec. the power is turned off.
    Calculate(v1,x,y) first part of the flight given - v0=100m/s, θ=53° , 3sec and 30m/s2.
    Second part is projectile motion.
     
  4. Sep 29, 2012 #3
    I see but how come I can't break up the first part into components?
     
  5. Sep 29, 2012 #4
    First part is just a straight line with constant acceleration.
     
  6. Sep 29, 2012 #5
    Ok thank you. :)
     
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