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## Homework Statement

Cassify the singularities of [itex]e^\frac{1}{z} [/itex] and find the Laurent series

## Homework Equations

[itex]e^\frac{1}{x} [/itex]=[itex]\sum \frac{(\frac{1}{x})^n}{n!}[/itex]

## The Attempt at a Solution

Theres a singularity at z=0, but I need to find the order of the pole

So using the general expression for the expansion of an exponential:

[itex]e^\frac{1}{z} [/itex]=[itex]\sum \frac{(\frac{1}{z})^n}{n!}[/itex] but this leads to a 1 as the first term, which is obviously not consistent.

I also tried considering re-defining a new variable for [itex]\frac{1}{z} [/itex], but I'm not really sure how to proceed from here

Many thanks :)