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Law of conservation of energy

  1. Apr 17, 2008 #1


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    1. The problem statement, all variables and given/known data

    A gardener exerts a force of 1.5 x 10^2 N (22 degress below the horizontal) in pushing a large 18 kg box of flower seeds a distance of 1.6 m. The coefficient of kinetic friction between the box and the floor is 0.55.
    use the law of conservation of energy to determine the final speed of the box if it starts from rest.

    2. Relevant equations

    Total energy= kinetic energy + potential energy

    3. The attempt at a solution

    But theres no potential energy...:confused:
  2. jcsd
  3. Apr 17, 2008 #2


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    You should think about how much is work is done on the box and how much is done against the box.
  4. Apr 17, 2008 #3


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    You should also compute the normal force the box exerts on the floor given it's being pushed from below. Use a force diagram. Don't worry about the lack of potential energy, there isn't any. Just get started.
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