Solve triangle having indicated sides and angles.
Law of Cosines
Law of Sines
The Attempt at a Solution
I did c^2=9^2+6^2-(2*9*6*Cos45 degrees)
Then I did 6.37/cos45 =9/SinB.. That proportion would give me 87.5 derees.. However, the back of my book and..
Says that B is 93.3 degrees..
However, if I were to approach the problem by solving for A (smallest angle) instead of immediately to B (mid sized).. I would get 41.7 degrees..
Then I could do B=180-A-C..or 93.3 degrees..
But still, if I set up a ratio of sin41.7degs/6=sinB/9, that's not 93.3, or 87.5, but 86.2
I'd like to know why math is stupid. And next time, what I should do to know whether 93.3, 87.5, or 86.2 would be the right answer.
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