1. The problem statement, all variables and given/known data You weigh 518 N at sidewalk level outside the World Trade Center in New York City. Suppose that you ride from this level to the top of one of its 410 m towers. Ignoring Earth's rotation, how much less would you weigh there (because you are slightly farther from the center of Earth)? 2. Relevant equations F = (GMm)/r2 Mass of Earth: 5.97x1024 kg Radius of Earth: 6378100 m 3. The attempt at a solution 518 = ((6.67x10-11)(5.97x1024)(m))/(63781002) m = 52.92 kg F = (GMm)/(r+h)2 F' = ((6.67x10-11)(5.97x1024)(52.80))/(63785102) F' = 517.94 N So my calculated difference is .0575 N, but apparently that's not right. Not sure where I've gone wrong here, any help is much appreciated.