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Law of Nuclear decay?

  1. Jan 3, 2007 #1
    Radioactive decay is normally characterised by 'the rate of decay is linearly proportional to the number of nuclides avaliable'. i.e dN/dt=-aN (a>0)

    How correct is this law? Are there better models of describing nuclear decay? If so what are they?
     
  2. jcsd
  3. Jan 3, 2007 #2

    mathman

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    The basic law is quite accurate. The physical assumption is that the probability of an atom decaying is independent of another atom decaying.
     
  4. Jan 4, 2007 #3
    So this law is like the inverse square gravitational and electrostatic laws in that they are very simple but extremely accurate and only when one goes down to several decimal points does it break down?
     
  5. Jan 4, 2007 #4

    CarlB

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    In practice, in most situations, it works very well. However, not always. The problem is that quantum mechanics is a quadratic theory, while radioactive decay follows a linear relation. Consequently, things only decay following the exponential law for times that are not too short and not too long.

    Here's some slides showing the issue:
    http://www.drake.edu/artsci/physics/petridis_other_files/dnp_talk_10_19_01.ppt


    Here are some references:
    http://arxiv.org/abs/quant-ph/0202105
    http://www.aip.org/pnu/1997/split/pnu327-2.htm
    http://arxiv.org/abs/physics/0505042
    http://arxiv.org/abs/quant-ph/0411145
    http://arxiv.org/abs/quant-ph/9806079

    From the peer-reviewed literature:
    http://prola.aps.org/abstract/PRA/v63/i6/e062110

    There are tons of articles on this. Search for "Zeno" or "non exponential decay".

    Carl
     
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