1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Lawn mower work Question

  1. Jan 8, 2016 #1
    1. The problem statement, all variables and given/known data
    A woman pushes a lawn mower(25-kg) with a force of 400 N at an angle 45 degrees below the horizontal for a displacement of 12 meters. The coefficient of friction between the lawn and the mower is 0.1. The answer is -634 J but I get a different answer.
    2. Relevant equations
    W = F (d)

    3. The attempt at a solution
    W = -(coefficient of friction) (mg) (12 m)
    W = - 0.1 * 25 * 9.8 * 12
    W = -294J
  2. jcsd
  3. Jan 8, 2016 #2


    User Avatar
    Staff Emeritus
    Science Advisor
    Homework Helper

    You should draw a free body diagram of the lawn mower with the woman pushing it, in order to find the correct normal force.
  4. Jan 8, 2016 #3
    Thank you very much that helped a lot. I realized my mistake.
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted

Similar Discussions: Lawn mower work Question
  1. Lawn Mower (Replies: 3)