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Laws of Exponants II

  1. Jun 13, 2013 #1

    reenmachine

    User Avatar
    Gold Member

    1. The problem statement, all variables and given/known data

    Simplify this expression and express the result with only positive exponants.

    2. Relevant equations

    The expression:

    ##\left( \frac {(-49^4 \ c^{-2} \ d)^3}{14^6 \ c^{-1} \ d^2} \right)^{-1}##

    3. The attempt at a solution

    ##\left( \frac {(-49^4 \ c^{-2} \ d)^3}{14^6 \ c^{-1} \ d^2} \right)^{-1}##

    ##\left( \frac {(-(7^2)^4 \ c^{-2} \ d)^3}{(2 \cdot 7)^6 \ c^{-1} \ d^2} \right)^{-1}##

    ##\left( \frac {(- 7^8 \ c^{-2} \ d)^3}{2^6 \cdot 7^6 \ c^{-1} \ d^2} \right)^{-1}##

    ##\left( \frac {- 7^{24} \ c^{-6} \ d^3}{2^6 \cdot 7^6 \ c^{-1} \ d^2} \right)^{-1}##

    ##\left( \frac {- 7^{18} \ c^{-5} \ d}{2^6} \right)^{-1}##

    ##\left( \frac {- 7^{-18} \ c^5 \ d^{-1}}{2^{-6}} \right)##

    ##\left( \frac {- 2^6 \ c^5}{7^{18} \ d} \right)##

    Is this correct?

    Thank you!
     
    Last edited: Jun 13, 2013
  2. jcsd
  3. Jun 13, 2013 #2

    jedishrfu

    Staff: Mentor

    Yes that seems correct.

    I did it a bit differently though by going outside in to eliminate the outermost -1 exponent:

    (A/B)^-1 = B/A

    and then I moved factors to the numerator or denominator to eliminate the - exponent then I simplified things

    to get what you got.
     
  4. Jun 13, 2013 #3

    reenmachine

    User Avatar
    Gold Member

    thank you!
     
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