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## Homework Statement

If a falling object overcome 72 metres in 6 second, how much distance it overcame in first 3 second.

## Homework Equations

s = ut+(at^2)/2

## The Attempt at a Solution

Here,

s = 72 m

u = 0

t = 6s

a = ?

We know,

s = ut+(at^2)/2

Or, 72 = 0*6 + (a*6^2)/2

Or, 72 = 36a/2

Or, 72 = 18a

Or, a = 4 m/s

In the second part,

u = 0

t = 3s

a = 4 m/s^2

s = ?

Again,

s = ut+(at^2)/2

= 0*t + (4*3^2)/2

= (4*9)/2

= 36/2

= 18 m (ans.)