The 300 μF capacitor is initially charged to 100 V, the 1200 μF capacitor is uncharged, and the switches are both open. So the picture is two capapcitor in either side of the circuit. There is a inductor 5.3 H in the middle wire that divide the switches in eaither side of the circuit
a) What is the maximum voltage to which you can charge the 1200 microF by proper closing and opening of the two switches?
b)How would you do it? Describe the sequence in which you would close and open switches and the times at which you would do so. The first switch is closed at .
w=sqaureroot of 1/LC
The Attempt at a Solution
I tried to find the charge on the first one by using Q=VC and then try to find the total C of the circiut Ceq= C1+ C2. Then use the charge of 1 devide by the total Ceq
However, I can't figure out the right answer....
Any help will be greatly appreciated...