1. The problem statement, all variables and given/known data 4700uF Capacitor is initially charged to 9.0V, then the voltage source is removed and the capacitor is connected across a 1.50H inductor. Solve for: Energy of the Circuit, Imax, and Time after Circuit connected whed Energy of the capacitor =Energy of the inductor 2. Relevant equations Imax=εmax/√(R2+(2πƒL= (1/2πƒC)) ƒ=1/2π√LC E=1/2 CV2+ 1/2LI2 Cap discharging Inductor charging 3. The attempt at a solution ƒ=1/2π√LC= 1.896Hz Imax=εmax/√(R2+(2πƒL= (1/2πƒC)) Plugging in 9.0v for ε, 1.9 for ƒ, 4700*10-6 for C and 1.5 for L, and crossing out R since no given resistance... I come up with Imax=30.95A E=1/2 CV2+ 1/2LI2 E=720.9 Did i do the first two correctly? and, not sure about the last part, would i just use and set that equal to and solve for t?