A fixed inductance 0.66 [tex] \mu H [/tex] is used in series with a variable capacitor in the tuning section of a radio. What capacitance tunes the circuit into the signal from a station broadcasting at 8.11 MHz? Answer in units of pF. I used the equation [tex] \omega = 1/ \sqrt LC [/tex] Solving for C gave me [tex] (1/ \omega)^2 /L [/tex] Then I converted all my numbers. 0.66[tex] \mu H [/tex] = 6.6e-7 H 8.11 MHz= 8110000 Hz So plugging in, (1/8110000)^2 / 6.6e-7 gave me 2.30e-8 F then converting to pF, gave me 23000, which isn't right.. can someone tell me what I'm doing wrong?