- #1
AiRAVATA
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Hello guys. I have a simple question regarding an LC circuit.
Imagine a voltage source [itex]V_0[/itex], a capacitor [itex]C[/itex] and an inductor [itex]L[/itex], all hooked up in series. I know that the equation governing the behvior of the system is
[tex]V_0=\frac{1}{C}q(t)+L\ddot{q}(t),[/tex]
and hence
[tex]q(t)=A\cos \omega t + B\sin \omega t + CV_0.[/tex]
What I'm having trouble with is the initial conditions. Is it fair to assume that in [itex]t=0[/itex] there is no charge nor current in the system?
If I put a switch in the system, how would the initial conditions change (assuming is open in [itex]t=0[/itex] and closed in [itex]t>0[/itex])?
Imagine a voltage source [itex]V_0[/itex], a capacitor [itex]C[/itex] and an inductor [itex]L[/itex], all hooked up in series. I know that the equation governing the behvior of the system is
[tex]V_0=\frac{1}{C}q(t)+L\ddot{q}(t),[/tex]
and hence
[tex]q(t)=A\cos \omega t + B\sin \omega t + CV_0.[/tex]
What I'm having trouble with is the initial conditions. Is it fair to assume that in [itex]t=0[/itex] there is no charge nor current in the system?
If I put a switch in the system, how would the initial conditions change (assuming is open in [itex]t=0[/itex] and closed in [itex]t>0[/itex])?