- #1
rich t
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It's been a while since i did physics at Uni and I'm a bit rusty with it all but I've recently been trying to get my head around LC circuits
i've looked at the wikipedia website and seen the solved differential for LC circuits but I'm a bit confused with the following assumptions...
current through inductor = -current through capacitor
voltage across capacitor = voltage across inductor
firstly, is there a current through the capacitor?! i can understand the idea of a current through the inductor but they aren't any electrons moving between the two plates are there, so how can there be a current?
secondly, if the voltage across capacitor = voltage across inductor how can there be any current flow? (i'm imagining two cells in a series circuit facing the opposite way) i have a feeling I've somehow misunderstood voltage here
i've been trying to get an intuitive idea of how these circuits work and I'm kind of thinking along these lines...
there is an intial build up of electrons on one plate of the capacitor (causing a voltage) there causes these electrons to move towards the other plate (a current flows). this current is limited because of the inductor, it cannot increase unchecked because of lenz's law, and so there is an opposing voltage due to the inductor (though i can't see how this could be the same size as the voltage across the capacitor?!)
but unlike a capacitor the current (and rate of change of voltage) increases, why?
i'm thinking if the rate of current increase were constant then the induced emf/voltage would be constant and since the voltage across the capacitor would decrease this would result in a drop in the rate of increase of current and so the inducred emf/voltage would decrease but since the current is still flowing the voltage across the capacitor would drop and so the rate of current increase would drop again...
if anyone could shed any light on this (particularly the point about the equal and opposite voltages) i'd be grateful
i've looked at the wikipedia website and seen the solved differential for LC circuits but I'm a bit confused with the following assumptions...
current through inductor = -current through capacitor
voltage across capacitor = voltage across inductor
firstly, is there a current through the capacitor?! i can understand the idea of a current through the inductor but they aren't any electrons moving between the two plates are there, so how can there be a current?
secondly, if the voltage across capacitor = voltage across inductor how can there be any current flow? (i'm imagining two cells in a series circuit facing the opposite way) i have a feeling I've somehow misunderstood voltage here
i've been trying to get an intuitive idea of how these circuits work and I'm kind of thinking along these lines...
there is an intial build up of electrons on one plate of the capacitor (causing a voltage) there causes these electrons to move towards the other plate (a current flows). this current is limited because of the inductor, it cannot increase unchecked because of lenz's law, and so there is an opposing voltage due to the inductor (though i can't see how this could be the same size as the voltage across the capacitor?!)
but unlike a capacitor the current (and rate of change of voltage) increases, why?
i'm thinking if the rate of current increase were constant then the induced emf/voltage would be constant and since the voltage across the capacitor would decrease this would result in a drop in the rate of increase of current and so the inducred emf/voltage would decrease but since the current is still flowing the voltage across the capacitor would drop and so the rate of current increase would drop again...
if anyone could shed any light on this (particularly the point about the equal and opposite voltages) i'd be grateful