1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Homework Help: Lead oxide + base

  1. Oct 19, 2005 #1
    what is the product of the reaction:

    PbO + NaOH -> ???


    PbO + NaOH + H2O -> ??

    is there any difference?:frown:

  2. jcsd
  3. Oct 19, 2005 #2
    Ok finally got latex how I wanted. It depends upon concentration of the base. Look up hydrolysis.

    Excess Lead:
    [tex] Pb(s) + 2OH^-(aq) \rightarrow Pb(OH)_2(s)[/tex]

    Excess NaOH:
    [tex]Pb(OH)_2(s) + H2O(l) \rightarrow Pb(OH)_3^-(aq)[/tex]

    Lead (II) Oxide:
    [tex]PbO(s) + H2O(l) + OH^-(aq) \rightarrow Pb(OH)_3^-(aq)[/tex]

    So if you use excess NaOH there will be no difference in your products.

    Lead (IV) Oxide:
    [tex]PbO2_(s) + 2H_2O(l) + 2OH^-(aq) \rightarrow Pb(OH)_6^{-2}(aq).[/tex]
    Last edited: Oct 20, 2005
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook