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Lead oxide + base

  1. Oct 19, 2005 #1
    what is the product of the reaction:

    PbO + NaOH -> ???

    or

    PbO + NaOH + H2O -> ??

    is there any difference?:frown:

    thanks
     
  2. jcsd
  3. Oct 19, 2005 #2
    Ok finally got latex how I wanted. It depends upon concentration of the base. Look up hydrolysis.

    Excess Lead:
    [tex] Pb(s) + 2OH^-(aq) \rightarrow Pb(OH)_2(s)[/tex]

    Excess NaOH:
    [tex]Pb(OH)_2(s) + H2O(l) \rightarrow Pb(OH)_3^-(aq)[/tex]

    Lead (II) Oxide:
    [tex]PbO(s) + H2O(l) + OH^-(aq) \rightarrow Pb(OH)_3^-(aq)[/tex]

    So if you use excess NaOH there will be no difference in your products.

    Lead (IV) Oxide:
    [tex]PbO2_(s) + 2H_2O(l) + 2OH^-(aq) \rightarrow Pb(OH)_6^{-2}(aq).[/tex]
     
    Last edited: Oct 20, 2005
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