(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A non ideal capacitor having a 'leaky' dielectric where RL is the leakage resistance measured across the dielectric. A 100pF parallel plate capacitor has a mica dielectric of relative permittivelty Er = 12 and resistivity of p = 1014 ohm m.

Calculate the leakage resistance of this capacitor

2. C = Er A/d & R = p d/A

3. Ans

C = 100 pF, resistivity = 1014 ohm m

Er = 12

C = Er A/d ---- (1)

where A is the area of cross section of the plate and d is the distance between the plates ( or the length of the dielectric)

R = p d/A ----(2)

From (1), d/A = Er/C = 12/(100 x 10-12) = 12 x 1010

Substituting in (2)

R = 1014 x 12 x 1010

Or R = 12 x 1024 Ohm

Or R = 1.2 x 1025 Ohm

The Equation seems right however answer looks wrong

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# Homework Help: Leakage Resistance

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