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Learningphysics please help

  1. Sep 23, 2007 #1
    014 (part 1 of 2) 10 points
    The speed of a point on a rotating turntable,
    which is 0.131 m from the center, changes at a
    constant rate from rest to 0.958 m/s in 1.95 s.
    At t1 = 1.6 s, find the magnitude of the
    tangential acceleration. Answer in units of
    m/s2.
    015 (part 2 of 2) 10 points
    At t1 = 1.6 s, ¯find the magnitude of the total
    acceleration of the point. Answer in units of
    m/s2.
     
  2. jcsd
  3. Sep 23, 2007 #2
    i know the formulas ... .

    v = 2pi r/t

    centripital acceleration = v2/r

    not sure if they help me on this one tho
     
  4. Sep 24, 2007 #3

    Astronuc

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    Staff: Mentor

    changes at a constant rate from rest to 0.958 m/s in 1.95 s.
    At t1 = 1.6 s, find the magnitude of the tangential acceleration.

    So the rate is constant during the 1.95 s and one needs to find speed at 1.6 s and from this v2/r.
     
  5. Sep 24, 2007 #4
    really? wow. im just learning too... lol
     
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