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Least Squares

  1. Sep 7, 2011 #1
    1. The problem statement, all variables and given/known data

    If I am dealing with an overdetermined system Ax=b, then I can (assuming A has full rank) find the unique approximative solution by least squares.

    Now, in my book it says that: "For a full column rank matrix, it is frequently the case that no solution x satisfies Ax=b exactly". I assume the book is saying that A having full rank is equivalent to it being overdetermined.

    Is that always the case?

  2. jcsd
  3. Sep 8, 2011 #2
    That is not always the case, I found out.
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