- #1

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- Thread starter soul
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- #1

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- #2

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- #3

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First of all it is an upper bound of the sequence {an}, meaning it is greater than every term of the sequence. More generally the upper bound of some set is some number greater than any number in the set.

Secondly it is the smallest such upper bound. So if A is a least upper bound for {an} and B is some other upper bound then A<B

- #4

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This is false, consider the set (0,1) then 1 is obviously the least upper bound, and also 0 is less than 1, but 0 is not in the set.

- #5

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With a search on google and with your help I understood the point. Thanks for your help guys.

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