(adsbygoogle = window.adsbygoogle || []).push({}); Legendre transform....

If we define a function f(r) with r=x,y,z,.... and its Legnedre transform

g(p) with [tex] p=p_x ,p_y,p_z,...... [/tex] then we would have the equality:

[tex] Df(r)=(Dg(p))^{-1} [/tex] (1) where D is a differential operator..the

problem is..what happens when g(p)=0?...(this problem is usually found in several Hamiltonians of relativity) then (1) makes no sense since a 0 matrix would have no inverse..how do you define Legendre transform then...

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# Legendre transform

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