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Leibniz derivative notation

  1. Mar 9, 2013 #1
    is there an algebraic meaning to expressing the derivative of a function

    as (d^2)y/(dx)^2 in the liebniz way
     
  2. jcsd
  3. Mar 9, 2013 #2
    [tex]\frac{d^{2}y}{dx^{2}}=\frac{d}{dx}(\frac{dy}{dx})[/tex]

    I think that's what you're asking?
     
  4. Mar 10, 2013 #3
    yes, I see that now. Does the d^2 mean something? or just signifiy second derivative, i can see how the dx squared would be like acceleration is seconds^-2
     
  5. Mar 10, 2013 #4
    If you multiple the d out on top you get d2y and if you multiply the bottom you get dx2
     
  6. Mar 10, 2013 #5
    but the d squared is not an exponent, its a derivative...are they the same?
     
  7. Mar 10, 2013 #6

    WannabeNewton

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    They are certainly not the same; don't think of them as exponents or fractions at all it is very misleading. It is just notation to relay the fact that you have acted the operator [itex]\frac{\mathrm{d} }{\mathrm{d} x}[/itex] on [itex]f[/itex] at [itex]x\in \mathbb{R}[/itex] twice.
     
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