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Lend a hand (help on orbits)

  1. Apr 13, 2009 #1
    I'm fairly new to astrophysics, but i'm genuienly intrested on knowing how to calculate orbits. I've been trying to do so on my own but I just find myself extremly frustrated. :confused: I'm trying to figure out what orbital vectors are and how i can calculate them using known orbital parameters. If i can get over this hurdle i should be all set.:approve:

    thanks.

    P.S. any sites that are helpful (lists of equations, sources etc.) would be appreciated.
     
    Last edited: Apr 13, 2009
  2. jcsd
  3. Apr 16, 2009 #2
    Although I have never attempted to calculate the orbits I would say it would be it would

    be a VERY tedious job to do. I would also think that you would need calculus to be able

    to calculate accurately.
     
  4. Apr 18, 2009 #3
    ok, i'm having difficulties in finding the velocity of the moon from a certain distance from the earth,

    the equation i'm using is the vis-viva equation:

    v=[tex]\sqrt({}\mu*(2/r-1/a))[/tex]

    [tex]\mu=GM[/tex]=3.98694E+14

    r=radial distance from focus to orbiting object=369397 km (periapsis of moon)
    a=semi-major axis=3847487 km

    the end value that i got is 45332.04235 m/s !!!!!
    somethings not right!
     
  5. Apr 18, 2009 #4

    D H

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    Try as I might I cannot reproduce your result. You are probably doing multiple things wrong.
    1. The equation is
      [tex]v=\sqrt{\mu\left(\frac 2 r - \frac 1 a\right)}[/tex]
      Did you take the square root of the whole thing?

      2. μE is 398,600.442 km3/s2, or 3.98600442×1014 m3/s2.
      A couple of things to note:
      • This value is known very precisely. The error in μE is very, very small compared to the error in G. (Almost 9 significant digits versus 4 or so.)
      • UNITS, UNITS, UNITS. You have a number, no units. Lack of attention to units is most likely one of the sources of your error.
    2. The Moon's semimajor axis is 384,399 km, not 3847487 km. This is almost certainly another source of your error.
     
    Last edited: Apr 18, 2009
  6. Apr 18, 2009 #5
    ok, i tried all you suggested however i still have a number of .2454 km/s or 245.5 m/s. I'm not sure this is right because of these values: http://nssdc.gsfc.nasa.gov/planetary/factsheet/moonfact.html" [Broken]
    it says that min. orbital speed is 0.964 km/s. I'm not sure what to think now.:confused:
     
    Last edited by a moderator: May 4, 2017
  7. Apr 18, 2009 #6
    Hi Solistics,

    For the moon problem you can assume a circular orbit for which

    [tex] v = \sqrt{\frac{\mu}{r}} [/tex] or [tex] v = \sqrt{\frac{G M}{r}} [/tex]

    where M is the mass of the Earth + moon. Since the Earth's mass is larger than the moon's mass, we can approximate M to be = the mass of the Earth.

    G is [tex] 6.67300×10^{-11} m^{3} kg^{-1} s^{-2} [/tex] and r = semi-major axis = 384,399 km

    Punch in the values for this and you obtain v = 1.018 km/s

    The value from wiki is 1.022 km/s, which means we were only off by 0.39%
     
  8. Apr 18, 2009 #7

    D H

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    First off, I messed up my LaTeX in post #4. Corrected.

    protonchain: A couple of points.

    Astronomers rarely use G (and planetary masses) for the simple reason that G (and the planetary masses) are not very accurate. G is embarrassing one of the least well-known physical constants (5 decimal places of accuracy). On the other hand, the product G*M can be measured to a very high degree of precision. For example, we know G*M for the Sun to about 12 places of accuracy and for the Earth to about 9 places.

    The other point: The Moon's mass is a significant fraction of the Earth's mass. Ignoring it will lead to inaccurate results. A better estimate of the Moon's orbital velocity with respect to the Earth is

    [tex]v=\sqrt{\frac{\mu_E+\mu_M}{a_{M}}} = 1024.5\,\text{km}/\text{s}[/tex]


    To Solistics:
    It looks like you are jumping in over your head. How old are you, and how much high a level have you reached in your physics education? Rather than jumping in like this, I suggest you start with Kepler's laws (google for that). Feel free to ask any questions.
     
  9. Apr 18, 2009 #8
    Is that a misplaced decimal point? Because it's 1.02 km/s not 1000 km/s

    Second of all my error was 0.39%, so I'm well within the limits and it's a good estimate.
     
  10. Apr 18, 2009 #9

    D H

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    Sorry, misplaced decimal (actually, extra k; that should have been m/s, not km/s). Too fast typing! And yes, it is a reasonably good estimate. Note that you cannot get much better than your estimate if you use G (rather than G*M).
     
  11. Apr 18, 2009 #10
    What bodies are you trying to calculate just the earth and moon?
     
  12. Apr 18, 2009 #11
    thanks for the help everyone. I found my problem. It seems like I switched a number in the vis-visa equation, 1/r instead of 2/r. Stupid me :rolleyes:. That fixed it. Now my values are exactly like what http://nssdc.gsfc.nasa.gov/planetary/factsheet/moonfact.html" [Broken] said.

    D H i'm intrested in where you found the value of mu. At first i did what protonchain did M*G which gave my results a big difference from yours. Knowing how you got that would be great :cool:.
     
    Last edited by a moderator: May 4, 2017
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