1. The problem statement, all variables and given/known data A relativistic conveyor belt is moving at speed 0.5c relative to frame S.Two observers standing beside the belt, 10 ft apart as measured in S, arrange that each will paint a mark on the belt at exactly the same instant (as measured in S). How far apart will the marks be as measured by observers on the belt? 2. Relevant equations gamma = 1/√(1-β^2) = 1.1547 L = L0/gamma 3. The attempt at a solution This problem seems very easy and I think I might be missing something as a result. I simply viewed the problem as the conveyor belt being stationary (and therefore the observers) and the people marking the belt to be moving at speed 0.5c. I then used the length contraction formula to calculate that the markings on the conveyor belt as the length between the two people marking would be length contracted. L = 10/ 1.1547 = 8.66 feet between the two markings. is this right or am I missing something?