Find the length of [tex] y = \frac{1}{3} (x^2 + 2)^{\frac{3}{2}} [/tex] from x=0 to x=3.(adsbygoogle = window.adsbygoogle || []).push({});

I used the formula [tex] s = \int_{a}^{b} \sqrt{1 + \frac{\,dy}{\,dx}} \,dx [/tex].

After plugging everything in, I got

[tex] s = \int_{0}^{3} (1 + \frac{1}{4} (x^2 + 2))}^\frac{1}{2} \,dx [/tex]

Now, this isn't an integral I've learned how to do, so

1) Did I do anything wrong, and

2) If yes, what?

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# Homework Help: Length of a curve

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