1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Homework Help: Length of a curve

  1. Jan 24, 2008 #1
    1. The problem statement, all variables and given/known data

    I need to find the length of [tex]\frac{\frac{1}{3}x^{3} + x^{2} + x + 1}{4x+4}[/tex] from x=0 to x=2 but i can not factor this down to be able to set up the integral, any suggestions, here is the derivative:
    It is possible I might have to factor the derivative rather than the function itself which is why i supplied both.
  2. jcsd
  3. Jan 25, 2008 #2


    User Avatar
    Homework Helper

  4. Jan 25, 2008 #3


    User Avatar
    Science Advisor

    I would write this as:
    [tex]\frac{1}{12} \frac{(x^3+ 3x^2+ 3x+ 1)+ 2}{x+1}=\frac{1}{12}\frac{(x+1)^3+ 2}{x+1}= \frac{1}{12}((x+1)^2+ \frac{2}{x+1})[/tex]
    That looks to me like it will be easier to handle.
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook