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Length of a pendulum

  1. Sep 7, 2011 #1
    1. The problem statement, all variables and given/known data
    by what fraction must you change the length of the pendulum to make it run true if it loses one minute every hour

    2. Relevant equations

    t=2pi/sqrt(g) * sqrt(l)

    3. The attempt at a solution
    I know that I am losing 1 second every 60 seconds so I need to shorten the period by a certain amount so that it swings 60 times every 60 second instead of the 59 times that it currently swings.

    so I want to say T=t-1/60 and then plug that in to find L (T and L are final while t and l are initial).

    but the correct answer is T=t(1-1/60), I don't know why this is or how we get it. I can do the rest of the problem if I can understand this one thing.

    thanks,
     
  2. jcsd
  3. Sep 7, 2011 #2
    Does this work?

    The frequency f(L) is 1/T(L) = [1/2pi]*[g/L]^.5 = 3540/3600 we get 3540 cycles per 3600 seconds with length L. But we want,

    f(L-L/a) = [1/2pi]*[g/L-L/a]^.5 = 3600/3600

    ?
     
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