by what fraction must you change the length of the pendulum to make it run true if it loses one minute every hour
t=2pi/sqrt(g) * sqrt(l)
The Attempt at a Solution
I know that I am losing 1 second every 60 seconds so I need to shorten the period by a certain amount so that it swings 60 times every 60 second instead of the 59 times that it currently swings.
so I want to say T=t-1/60 and then plug that in to find L (T and L are final while t and l are initial).
but the correct answer is T=t(1-1/60), I don't know why this is or how we get it. I can do the rest of the problem if I can understand this one thing.