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Length of curve integral

  1. Jan 1, 2014 #1
    1. The problem statement, all variables and given/known data

    Find the length of the curve y = x^3/a^2 + a^2/12x

    between a and a/2


    2. Relevant equations

    Length L = integrate (1+ dy/dx)^2)^0.5

    3. The attempt at a solution

    I got to

    integrate (9x^4/a^2 + 1/2 + a^4/144x^4)^0.5

    but I can't simplify it
     
  2. jcsd
  3. Jan 1, 2014 #2

    LCKurtz

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    Is that last term supposed to be ##\frac {a^2}{12x}## or ##\frac{a^2x}{12}##?
    Did you leave out the ##1##? It would help if you showed your work.
     
  4. Jan 1, 2014 #3
    the last term is a^2 / (12x) x in the denominator.

    yeah i left out the 1, that was a typo.

    L = intergrate (1+ (dy/dx)^2)^0.5

    thanks
     
  5. Jan 1, 2014 #4

    LCKurtz

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    Re-check your arithmetic for that first term and you should be able to work out that the quantity under the radical is a perfect square.
     
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