An object is placed 12.8 cm to the left of a diverging lens of focal length -6.35 cm. A converging lens of focal length 12.8 cm is placed a distance of d to the right of the diverging lens. Find the distance d that places the final image at infinity
The Attempt at a Solution
I understand that I have a few unknowns and need to solve this a couple of times to discover the di:
So [/B]1/f=1/di +1/do : MAIN EQUATION
Di: 1/(-6.635)=1/di+1/(12.8cm). gives me di of -4.244 cm
Do2: 4.244+25.6=29.844 cm
Eventually I end up with -22.41 cm.
I don't know if I am supposed to solve this for 2nd time through lens. Therefore, I thought I ended up -22.41 cm. However, that is not right. Please help.
I have a small request: Please read the problem very carefully. I do not want to answer what kind of mirror this is if the problem already answers it. I have had to answer questions regarding variables that I clearly explained in the problem. Please refrain from it. I want to learn so if you ask me a question to help me better understand the problem than that is fine. BUT DO NOT ASK ME ABOUT WHAT THE VARIABLES ARE BECAUSE I FEEL LIKE I AM REPEATING MYSELF RATHER THAN LEARNING ANYTHING NEW.