What Happens to Parallel Rays in Compound Lens and Mirror Setups?

  • Thread starter mihajovics
  • Start date
  • Tags
    Mirror
In summary, the conversation is about a setup with a thin lens and two mirrors, one convex and one concave, that fit perfectly onto the lens' concave and convex sides. The question is what happens to parallel rays in this setup. The conversation also mentions the possibility of spraying silver or other metal on one side of the lens to create a thin layer that reflects light perfectly. The person asking the question is having trouble understanding the setup and is seeking help. The conversation also includes some hints and things to keep in mind when thinking about the problem.
  • #1
mihajovics
7
0

Homework Statement



You have a thin lens with a concave and a convex side (let's say with radii r and R). You also have 2 mirrors, a convex one, that fits perfectly into the lens' concave side, and a concave one, that fits perfectly onto the lens' convex side (so the corresponding radii of the mirrors are R and r).

Representation:
D = lens
I = mirror1
) = mirror2

position1:
ID <--- rays are coming from this side

position2:
rays are coming from this side ---> D)

Okay, it's lame, but I couldn't get a better one :smile: The lens and mirrors when attached to each other fit perfectly together, they complement one another, so there's no distance between them at all.
You could also think of the problem as spraying some silver or other metal on one side of the lens, creating a thin layer that reflects light perfectly.

The question is, what happens to the parallel rays in the two aforementioned setups?

2. Homework Equations / 3. The Attempt at a Solution

Well, the problem is I don't understand what's going on. I know general optics, the usual geometrical stuff, but can't find a useful tool for this problem from that bag of tricks.
It's kind of urgent, so thanks in advance for your help. :smile:
 
Physics news on Phys.org
  • #2
Well, there are a few things to keep in mind, to help think about this:

1. When you have two closely-spaced lenses next to each other, what is the effective focal length of the two-lens system?

2. A mirror is like a lens with focal length f = ___?

3. With a mirror next to a lens, rays will pass through the lens twice, so effectively it is as if you have two lenses and the mirror.
 
  • #3




Thank you for providing the homework statement and your attempt at a solution. This is a very interesting problem and it involves the concept of compound lenses and mirrors.

In the first setup, where the lens and mirrors are attached to each other, the parallel rays will first pass through the lens and then reflect off of the mirrors. The lens will refract the light and the mirrors will reflect the light, causing the rays to converge at a point behind the lens. This is known as a compound lens system, where multiple lenses and mirrors are used to manipulate light in a specific way. The exact position of the focal point will depend on the radii of the lens and mirrors and their respective distances from each other.

In the second setup, where a thin layer of reflective material is added to one side of the lens, the parallel rays will simply reflect off of the lens and converge at a point behind the lens. This is similar to a simple mirror, where the angle of incidence is equal to the angle of reflection. However, because the lens is curved, the rays will converge at a single point rather than being reflected in a single direction.

I would suggest using the thin lens equation and the mirror equation to solve this problem. These equations take into account the curvature and distance of the lens and mirrors and can help determine the position of the focal point. Additionally, understanding the concept of compound lenses and mirrors can also aid in solving this problem.

I hope this helps and good luck with your homework!
 

What is the "lens and mirror problem"?

The "lens and mirror problem" is a common problem in optics that involves finding the position and size of an object in relation to a lens and mirror system. It is often used to calculate the focal length, magnification, and image distance of the system.

What is the difference between a lens and a mirror?

A lens is a transparent object made of glass or plastic that refracts light, while a mirror is a smooth, shiny surface that reflects light. In terms of function, a lens bends and focuses light, while a mirror creates an exact copy of an image.

How do you calculate the focal length of a lens or mirror?

The focal length of a lens or mirror can be calculated by using the formula: 1/f = 1/di + 1/do, where f is the focal length, di is the image distance, and do is the object distance. This formula is known as the lens/mirror equation.

What is the difference between a real and virtual image?

A real image is formed when light rays actually converge at a point to form an image, and it can be projected onto a screen. A virtual image is formed when light rays only appear to come from a certain point, and it cannot be projected onto a screen.

What are some common applications of lenses and mirrors?

Lenses and mirrors have many practical applications in everyday life, including eyeglasses, cameras, telescopes, microscopes, and corrective lenses in projectors. They are also used in scientific experiments and in various industries, such as medicine and astronomy.

Similar threads

  • Introductory Physics Homework Help
Replies
13
Views
2K
  • Introductory Physics Homework Help
Replies
1
Views
1K
Replies
7
Views
950
Replies
20
Views
3K
Replies
18
Views
5K
Replies
1
Views
2K
Replies
7
Views
4K
  • Advanced Physics Homework Help
Replies
1
Views
3K
  • Classical Physics
Replies
21
Views
1K
Replies
6
Views
8K
Back
Top