1. The problem statement, all variables and given/known data A long, straight wire lies on a table and carries a current I. As the drawing shows, a small circular loop of wire is pushed across the top of the table from position 1 to position 2. Determine the direction of the induced current, clockwise or counterclockwise, as the loop moves past position 1 and position 2. 2. Relevant equations No equations, but the right hand grip rule is relevant. 3. The attempt at a solution So I got the first part of the question right. I know that because the wire's current is going right, the right hand grip rule suggests that the magnetic field is pointing out of the screen/page. At position A, the table top has no field and the wire will want to resist the flux change. Therefore, a field will point downwards, opposite the direction of that of the wire, leading to a clockwise current at A. However, B also has a clockwise current. My reasoning was that if the looped wire is within the field generated by the wire, its magnetic field would also be out of the screen/page, and therefore if it is pushed back to the flux-less table top, the flux would decrease. To oppose this, I thought that the secondary magnetic force would be out of the page, and the loop at B would be counterclockwise. So why is it actually clockwise?