Let f:[rr]-> [rr]

  • #1
KLscilevothma
322
0
Let f:[rr]--> [rr]

It isn't a homework problem. :smile:
Let f:[rr]--> [rr] be a function such that f(xy)=f(x)+f(y) for all x,y belong to real numbers
a) Show that for all integers n, f(xn)=nf(x)
b) Suppose the inverse of f exists. Show that for all integers n, [f-1(x)]n=f-1(nx)

I know how to do part (a) but not part (b). Could someone please give me some hints/solution. I can't do problems involving "inverse of a function" unless they are very simple, like to find f-1 of f(x)=(1-x)/(1+x) where x does not equal to 1 or -1
 
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Answers and Replies

  • #2


Originally posted by KL Kam
It isn't a homework problem. :smile:
Let f:[rr]--> [rr] be a function such that f(xy)=f(x)+f(y) for all x,y belong to real numbers
a) Show that for all integers n, f(xn)=nf(x)
b) Suppose the inverse of f exists. Show that for all integers n, [f-1(x)]n=f-1(nx)

I know how to do part (a) but not part (b). Could someone please give me some hints/solution. I can't do problems involving "inverse of a function" unless they are very simple, like to find f-1 of f(x)=(1-x)/(1+x) where x does not equal to 1 or -1

a) thats the power rule formula for solving dx
b) this is antidx. remember its the opposite of dx. if your good with the power rule just do it backwards and subtract.

A good http://math.vanderbilt.edu/~pscrooke/toolkit.shtml [Broken] for you to use.
dx :wink:
 
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  • #3
mathman
Science Advisor
8,065
542
inverse

Let x=f(y), or y=f-1(x)
f(yn)=nf(y)=nx
Take inverse on both sides and get
yn=(f-1(x))n=f-1(nx)
 

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