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Jurrasic
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And what is the minimum value?
( -b/2a is for a maximum problem, but how do you get through this kind of problem?)
( -b/2a is for a maximum problem, but how do you get through this kind of problem?)
For the quadratic, ax2 + bx + c:Jurrasic said:And what is the minimum value?
( -b/2a is for a maximum problem, but how do you get through this kind of problem?)
The minimum value of the function cannot be determined without knowing the input value, as the function can have different values for different inputs.
The minimum value of the function can be found by finding the input value that results in the lowest output value. This can be done by using the vertex form of the function, -b/2a, where a, b, and c are the coefficients of the quadratic equation.
Yes, the minimum value of the function can be negative if the input value results in a negative output value. In this case, the minimum value would be the lowest negative value.
The vertex of the parabola is the point where the function reaches its minimum or maximum value. In this case, the vertex can be found by using the formula -b/2a to find the x-coordinate and then plugging that value into the original function to find the y-coordinate.
No, the minimum value of the function will be different for different input values. This is because the function is a parabola and the lowest point (minimum value) will shift depending on the input value.