Estimate the limit using L'Hopital's rule:(adsbygoogle = window.adsbygoogle || []).push({});

1.limit of x is going to infinity of xtan(1/x)

Okay, I have no idea how to do #1, but i know the indetermiate form is infinity*0.

2.limit as x tends to 0+ of (lnx - ln sinx)

For #2 the indeterminate form is infinity-infinity, so i took the derivative of the function and got:

(1/x) - (cosx/sinx) which yields the same indeterminate form of infinity - infinity.

So my question is, should i get both with a common denominator, or should i derive (1/x) - (cosx/sinx) again and plug 0 to see if it works?

Any suggestions? For both 1 or 2?

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# Homework Help: L'Hopital! problem help

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