- #1
IntegrateMe
- 217
- 1
Estimate the limit using L'Hopital's rule:
1. limit of x is going to infinity of xtan(1/x)
Okay, I have no idea how to do #1, but i know the indetermiate form is infinity*0.
2. limit as x tends to 0+ of (lnx - ln sinx)
For #2 the indeterminate form is infinity-infinity, so i took the derivative of the function and got:
(1/x) - (cosx/sinx) which yields the same indeterminate form of infinity - infinity.
So my question is, should i get both with a common denominator, or should i derive (1/x) - (cosx/sinx) again and plug 0 to see if it works?
Any suggestions? For both 1 or 2?
1. limit of x is going to infinity of xtan(1/x)
Okay, I have no idea how to do #1, but i know the indetermiate form is infinity*0.
2. limit as x tends to 0+ of (lnx - ln sinx)
For #2 the indeterminate form is infinity-infinity, so i took the derivative of the function and got:
(1/x) - (cosx/sinx) which yields the same indeterminate form of infinity - infinity.
So my question is, should i get both with a common denominator, or should i derive (1/x) - (cosx/sinx) again and plug 0 to see if it works?
Any suggestions? For both 1 or 2?