# L'Hopital Rule - Limits

## Homework Statement

http://puu.sh/1irk2 [Broken]

## The Attempt at a Solution

I am having trouble doing this question. I tried doing the L'Hopital but didn't work. When I subbed in 0 in the function, I got 0/0.

first time:
I got that: http://puu.sh/1iroz [Broken]

It still gave me the indeterminate form (0/0). Could someone give me a hint on solving this limit, I know the answer is 0 (used wolframalpha) but I am unsure why it is.

Thanks

Last edited by a moderator:

lurflurf
Homework Helper
Use L'Hopital's rulke again on the new limit.

Dick
Homework Helper

## Homework Statement

http://puu.sh/1irk2 [Broken]

## The Attempt at a Solution

I am having trouble doing this question. I tried doing the L'Hopital but didn't work. When I subbed in 0 in the function, I got 0/0.

first time:
I got that: http://puu.sh/1iroz [Broken]

It still gave me the indeterminate form (0/0). Could someone give me a hint on solving this limit, I know the answer is 0 (used wolframalpha) but I am unsure why it is.

Thanks

Use algebra to simplify your answer. I don't think the limit is zero.

Last edited by a moderator:
FOIWATER
Gold Member
I also did not get zero

I would not suggest using L'hospital's rule again, it can be simplified to give you a limit which is not zero I believe

Nevermind, you are right. It is -1. I redid it, when I simplified it, all the x's that led to the evil division of zero disappeared.

Thanks