evaluate the limit as x=>0 of sqrt(x^2+x) - x(adsbygoogle = window.adsbygoogle || []).push({});

so i multiplied by the conjugate to get:

x^2 + x - x^2 / sqrt(x^2 +x) + x

which simplifies to:

x / sqrt (x^2 + x) + x = infinity/infinity

taking LH, you get:

1 / 1/2(x^2+x)^(-1/2) * (2x+1) + 1 = infinity/infinity again

looking ahead, it doesnt look like LH is going to help

any suggestions?

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# Homework Help: L'Hopital's Rule

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