1. The problem statement, all variables and given/known data Find the limit as x->0+ of (ln(x))^x *The answer is 1* 2. Relevant equations l'Hôpital's rule 3. The attempt at a solution lim (ln(x))^x = 0^0 I took the ln of that quantity to bring down the x lim = x*ln(ln(x)) lim = ln(ln(x)) / (1/x) Then I used l'Hôpital's rule 1/(x*ln(x)/(1/x^2) = 1/(x^3*ln(x)) I got stuck here. If I plug in zero I get 0^3 and a undefined answer in the denominator. Do I have to do l'Hôpital's rule on the bottom again?