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Lift formula

  1. Jun 2, 2010 #1
    What's the equation for the force of a lift. Drag formula is 1/2 ρ∆v^2 C A. And if you need the constant how would i determine the lift constant for a semi circle shape which spins sideways and has an acceleration of approximately 8.5 m/s down (should be gravity which is 9.8 ms/s). It is moving forward at an initial speed of 62.9 m/s if that helps.
     
  2. jcsd
  3. Jun 3, 2010 #2

    Astronuc

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    Is the downward acceleration = 8.5 m/s2?

    Lift is a force. If an object is in free fall without an opposing force, it would accelerate at g, assuming it's near sea level. If the object is accelerating downward with a rate less than 9.8 m/s2, then there must be an opposing force - drag or lift.

    What is the significance of the diffrence between g and 8.5 m/s2?
     
  4. Jun 3, 2010 #3
    Because one shape had a gravitational pull or downward acceleration of 11.5 m/s and one 8.5 and I'm attempting to calculate the force on both objects and why.
     
  5. Jun 4, 2010 #4
    Try applying Newton's Second Law to the falling object.
    You know that it is acted on by two forces, gravity and the lift force. Draw a free body diagram, and remember that [tex]\Sigma \vec F = m\vec a[/tex], the sum of all forces on a body is equal its mass times its acceleration. Knowing the acceleration, you can find what you're looking for.
     
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