Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Ligand integrin dimerization

  1. Dec 3, 2007 #1
    1. The problem statement, all variables and given/known data

    3 different RGD-containing ligands (including Integrilin) are used to form receptor-ligand complexes, and measured dimerization of ligand-bound receptors as a fuction of temperature in the range 20-40C using a variety of methods. The 3 ligands are cHArGd, cRGD, and Integrilin. The dimerization reactin of ligand-bound receptors can be written as

    2RL-> dimer

    The values of the equilibrius constant K as a function of temperature for each of the 3 ligands are given in the following table

    T (C) Ka, cHArGD (M-1) Ka, cRGD (M-1) Ka, Integrilin (M-1)
    20 1.74*10^4 1.79*10^4 5.0*10^4
    25 5.9*10^4 7.08*10^4 8.6*10^4
    30 1.95*10^5 2.73*10^5 1.47*10^4
    35 5.97*10^5 9.85*10^5 2.45*10^5
    40 1.79*10^6 3.47*10^6 4.00*10^5

    a) which ligand leads to the greates degree of dimerization of the integrin-ligand complex at 20C? at 40C? Calculate the fraction of total integrin-ligand complexes is 1*10^-6 M.

    b) for each of the ligands, calculate the Gibbs free energy at 20C

    2. Relevant equations
    none given.

    3. The attempt at a solution

    Ka is the association constant, so the first part is easy. Integrilin at 20C and cRGD at 40C have the greatest degree of dimerization.

    I'm not sure how to find the tfraction of total integrin-ligand complexes. The definition of Ka is [complex]/[ligand][integrin] so would the Ka be the same for the [dimer]/[.5*complex][.5*complex] of the same ligand type? Would this a correct dimer concentration? I'm a bit lost here

    i know change in Gibbs free energy is [tex]\Delta[/tex]G=[tex]\Delta[/tex]H-T[tex]\Delta[/tex]S. Assuming H does not change, then would [tex]\Delta[/tex]S just be the number of complexes that have changed to dimers since 2 molecules have formed 1 molecule, lowering the entropy. I don't know how to find this change though.

    ::EDIT:: would the equation [tex]\Delta[/tex]G=-RTlnKeq work for this equation assuming Keq=Ka in this case? I found it under a description of micelle formation.

    Any help would be appreciated
    Last edited: Dec 3, 2007
  2. jcsd
  3. Dec 4, 2007 #2


    User Avatar
    Science Advisor
    Homework Helper
    Gold Member

    That is the way I read the problem. I don't know of any way to calculate entropy by inspection. It can be derived as:

    [tex]\Delta S = \frac{\Delta H - \Delta G}{T}[/tex]

    where [tex]\Delta G[/tex] is derived from [tex]\Delta G=-RTlnKeq[/tex]
    Last edited: Dec 4, 2007
  4. Dec 4, 2007 #3

    for part A, I was thinking that I could use Ka=[X]/[.5*initial complex-x]^2 to find X which would be the dimer concentration. Then I could use that over the initial complex concentration which is given to find the fraction. Would this work?
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook