- #1
Bri
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Could someone tell me if I did this right?
A narrow beam of sodium yellow light, with wavelength 589 nm in vacuum, is incident from air onto a smooth water surface at an angle of incidence of 35.0 degrees. Determine the angle of refraction and the wavelength of the light in water.
I did...
sin(35 degrees)=1.333*sin(theta)
theta = 25.486 degrees
589 nm = 1.333*lambda
lambda = 441.86
I'm just not sure I used the right equation/setup.
And I can't figure out this problem...
Unpolarized light in vacuum is incident onto a sheet of glass with index of refraction n. The reflected and refracted rays are perpendicular to each other. Find the angle of incidence.
I figured Theta1 + Theta2 = 90 degrees
and I tried to find a way to solve it using sin(Theta1) = n*sin(Theta2) but it's not working out.
Thanks.
A narrow beam of sodium yellow light, with wavelength 589 nm in vacuum, is incident from air onto a smooth water surface at an angle of incidence of 35.0 degrees. Determine the angle of refraction and the wavelength of the light in water.
I did...
sin(35 degrees)=1.333*sin(theta)
theta = 25.486 degrees
589 nm = 1.333*lambda
lambda = 441.86
I'm just not sure I used the right equation/setup.
And I can't figure out this problem...
Unpolarized light in vacuum is incident onto a sheet of glass with index of refraction n. The reflected and refracted rays are perpendicular to each other. Find the angle of incidence.
I figured Theta1 + Theta2 = 90 degrees
and I tried to find a way to solve it using sin(Theta1) = n*sin(Theta2) but it's not working out.
Thanks.