- #1

Romperstomper

What I did: The voltage is double, so I figured that if the voltage is doubled, the power must be doubled since [tex] P = I * \Delta V[/tex] and the current remains the same. Since [tex] \Delta V[/tex] changes between each bulb, I decided to use the net power and solved for I.

[tex]520 = I * 240 = 2.17A[/tex]. This is way off from the answer of .769A. Can anyone tell me what I did wrong?