1. The problem statement, all variables and given/known data A source of light shines through two apertures resulting in an intensity distribution pattern on a viewing screen. The central bright fringe is called the m=0 or zeroth order maximum. In the schematic diagram 1, the light source is to the left of the page and the point P represents the position of the second order intensity maximum on the screen. Two rays r1 and r2 are depicted incident at P. Calculate the separation d of the two apertures, given the wavelength of the light is 600nm, L = 2m, Y = 5cm. Remember that δ is the path difference between the rays (vectors) r1 and r2. Hint: We need to be able to relate δ to the order number and the wavelength of the light. 2. Relevant equations 3. The attempt at a solution From wikipedia it says that dsinθm = mλ I assume I need mλ to find out separation d of the two apertures. λ = 600nm, L = 2m, Y = 5cm m = 0 I'm not sure how to comprehend the wavelength. I really need someone to explain what I need to do here. Any help would be grand!!