 #1
hidemi
 208
 36
 Homework Statement:

If 550nm light is incident normally on a diffraction grating and exactly 6 lines are produced, the ruling separation must be:
The answer is between 2.20 ´ 106 m and 3.30 ´ 106 m
 Relevant Equations:
 d·sin(θ) = n·λ
I get one of the ranges by calculating:
sin(90°) = 1
d·sin(θ) = d × 1 = d = n·λ
d = 6 × 550nm = 3,300 nm = 3.3 microns = 3.3 × 10⁻⁶ m
But, how can I get the other range of 2.2 × 10⁻⁶ m
Could anyone explain it to me? Thanks
sin(90°) = 1
d·sin(θ) = d × 1 = d = n·λ
d = 6 × 550nm = 3,300 nm = 3.3 microns = 3.3 × 10⁻⁶ m
But, how can I get the other range of 2.2 × 10⁻⁶ m
Could anyone explain it to me? Thanks