Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Light sensor

  1. Jul 18, 2007 #1

    I am using a light sensor connected to an analog input of a microcontroller. My circuit turns an output high when there is a voltage of 2.5V or higher at the analog input i.e when there is a light shining on the sensor. But sometimes my output goes high even though I have no light shining on the sensor.
    I would like the the sensor to be less sensitive so that it operates only when it senses a voltage of at least 2.5V or higher. How can I go about achieving this result? Would using a schmitt trigger be a good idea?I'd appreciate your advice!

    Thanks in advance,
  2. jcsd
  3. Jul 18, 2007 #2


    User Avatar

    You didn't say what the sensor is or what the interface
    circuit is betweel the microcontroller and sensor.

    You also are unclear about the whole 2.5 volt thing:

    "My circuit turns an output high when there is a voltage of 2.5V or higher at the analog input i.e when there is a light shining on the sensor."
    "I would like the the sensor to be less sensitive so that it operates only when it senses a voltage of at least 2.5V or higher. "

    ...which makes it sound like there's already a threshold
    level of 2.5V to actuate the response to the sensor.

    If it's truly an "analog input" on the microcontroller,
    then it may be going in to an analog to digital converter,
    and you should be able to change (within limits) the
    sensitivity of the microcontroller to the input by just
    reprogramming a different threshold value of ADC counts
    for actuation.

    If it's a digital input to the microcontroller that's tied to
    an analog signal source, yes, by all means, you should
    already be using something like a schmitt trigger between
    the amplified / conditioned analog sensor signal and a
    digital input bit.

    I don't know what the analog sensor signal output
    circuitry looks like, or whether it's easy to add circuitry to
    your board; you mention adding a schmitt trigger, so I
    guess you can add entirely new ICs without difficulty.

    Without changing the existing analog output of the
    sensor circuit you could add an operational amplifier
    configured for non-inverting signal gains of x2, then
    take the output of the op-amp and use a two-resistor
    voltage divider of e.g.
    10kohms series + 10kohms pot wiper to ground to
    create an adjustable electrical voltage divider so that
    your x2 buffered/amplified sensor input signal is divided
    by at least x2 up to xInfinity.

    Then you'd take that signal from the junction of
    the two-resistor voltage divider, feed it into a
    schmitt trigger, and the output of the schmitt trigger into
    your microcontroller.

    Another probably more desirable (from the sound of your
    circuit) option would be to implement an
    analog comparator circuit with hysteresis,
    logic level compatible output, and
    use a comparator IC with a built in voltage reference
    (unless you have a handy one in your microcontroller
    board) so that the sensor signal level that triggers the
    microcontroller input bit is adjustable via the comparator
    reference level. You'd use a
    fixed resistor and potentiometer to set the reference value
    at the other input of the comparator anywhere from
    +2.5Vdc or higher/lower if such adjustment benefits

    Here's an article showing comparator designs with
    hysteresis added:

    The resistor divider between the output and the input
    pin and ground gives the hysteresis which has an
    effect similar to a schmitt trigger.

    Vref would he your 2.5V or other desired reference level
    which you could generate from another resistor divider
    from a +3.3 or +5 or whatever voltage reference you
    have handy and which would be compatible with your
    parts voltage levels; again, there are comparators with
    built in voltage references if that helps.

    Use a comparator with a specified power supply voltage
    capability the same as your microcontroller, and power
    them from the same power supply feed.

    Use a comparator with a relatively fast output rise-time
    of under 1 microsecond, and which has its output high
    and output low logic levels compatible with your

    Of course if your sensor signal already is a voltage
    mode signal which can drive a relatively low output
    impedance, you could probably directly use a
    two-resistor or resistor<--->pot<---->ground
    voltage divider directly on the sensor output signal
    you now have, e.g. series resistor of 47kohms, pot of
    470kohms to ground, and then you'll have from
    0.9x to 0.0x of the present input voltage available on
    the pot wiper. Then you'd feed THAT voltage into
    a schmitt trigger and that into your uC.

    Of course you'd need the
    adjusted signal level to be able to exceed the schmitt
    trigger's VIH (minimum voltage input high) level,
    or the sensor could never trigger the schmitt trigger.
    Evidentally it's already over 2.5VDC in magnitude, but
    I have no idea what your circuit's logic levels are or
    by how much your sensor signal can exceed 2.5V, or
    what the sensor signal output impedance is etc....
    so it's hard to say what's best.
  4. Jul 18, 2007 #3
    "You didn't say what the sensor is or what the interface
    circuit is betweel the microcontroller and sensor."

    The microcontroller I'm using is a PIC16f877A.The light sensors in my circuit are solar cells (Part#CPC1822).I have connected 4 solar cells to four analog inputs (PortA pin 0,1,5,6) of my PIC.The code in my PIC reads the voltage from the solar cells and does an A/D conversion and then if the voltage is approximately greater than 2.5V then turns certain output bits of the PIC high.The voltage is 2.5V-5V iwhen I shine a light on the solar cell.This voltage is converted from A-to-D by the code in the PIC and I have certain LEDs flashing as a result.

    "You also are unclear about the whole 2.5 volt thing:"

    I've actually done the analog-to-digital conversion theoretically and taken readings so that I know what to expect. For example if I input a voltage of 2.215V at one of the analog inputs of the PIC and convert it I get the binary value of '0111'.My code works fine and works perfectly when I have four 5K pots connected to the four analog input pins of the PIC. I get the desired output bits to flash.But when I connect up the solar cell (I have 0.1uF capacitors in series with each cell to filter out the high-frequency noise) to the PIC analog inputs I get the same results.But the only problem from what I gathered is that the solar cells are quite sensitive and sometimes my output bits which are only suppose to flash in presence of a light start flashing without the light source.I would like to eliminate that problem so that the solar cells only respond when it senses a voltage of 2.5 V or higher

    So I would like to figure out how to have a circuit between the PIC and the solar cells(one that is easy to implement as I have four solar cells) that looks at just one threshold trigger voltage of 2.5V and ignores voltages below it.The Schmitt trigger ,from what I understand , would need an inverter if I were to add it to my circuit and it deals with two threshold voltages.

    Thanks a bunch for your detailed reply!Sorry for not clarifying things in my previous post! What would be the best way to get around this problem according to you?

    I appreciate your help!

  5. Jul 18, 2007 #4


    User Avatar

    "(I have 0.1uF capacitors in series with each cell to filter out the high-frequency noise)"

    You mean the capacitors have one end grounded and the
    other end tied to the solar cell output?
    That'd be more of a case of the capacitor being in
    parallel with the solar cell, which would probably be what
    you want for such filtration.

    What's the power supply voltage of the PIC?
    What's the specified input voltage range of the PIC ADC
    based on your power supply and reference voltage

    Since you said the lighted voltage of the solar cells
    is 2.5-5V, I assume that means that the PIC analog
    input can handle such voltages.

    Anyway since you apparently have no other active
    circuitry between the solar cells and the sensor outputs,
    and the solar cells can handle low impedance loads,
    you could just use two-resistor a resistive voltage divider
    to attenuate the input voltages by some multiplier e.g
    0.5x or 0.7x or whatever. Connect a 4.7k resistor to
    the solar cell, and a 22k pot to ground, and feed the
    wiper of the pot out to the ADC inputs of the PIC, and
    you'll have an attenuated version of the solar cell voltages
    going to your ADC inputs. Whatever the PIC ADC values
    are now, they'd become some fraction of those values
    after attenuation. You'd still have to choose some ADC
    threshold value as being the level at which you decide
    that the solar cell is illuminated enough to take action,
    but, as you wished, that'd happen at a higher illuminance
    level than it presently does after the signal is attenuated.

    Since you are feeding analog voltages into an
    analog input of the PIC for ADC conversion, you do NOT
    need a schmitt trigger or comparator on the analog signal
    inputs. Schmitt triggers or logic-output comparators are
    for taking analog or slowly-rising (compared to a fast
    digital logic circuit) input signal and generating a sharp
    and jitter-free digital output bit from those analog signals
    such that the digital output from the trigger/comparator
    would be compatible to use in general digital logic circuitry.

    However as long as the PIC ports are programmed to be
    analog inputs of the ADC, it's permissible to feed any
    DC or slowly varying AC signal within the ADC input
    voltage range to those pins without schmitt triggering
    or comparator use.

    Now if you wanted to configure the PIC input pins
    as logic input bits, THEN you'd benefit from
    a schmitt trigger or logic compatible comparator before
    the location of the PIC digital input bits.

    You asked for a circuit to selectively send a logic
    signal to the PIC if the analog input exceeded 2.5VDC,
    which would be the logic compatible comparator with
    ~500mV of hysteresis that I mentioned before. However
    since you're feeding the signals to ADC analog inputs, it'd
    be rather incompatible with the idea of using analog
    inputs to the PIC to convert the analog signals to
    digital bits outside of the PIC. If you really want the
    PIC to have digital input bits coming from a threshold
    detector comparator with hysteresis, you might as well
    configure the PIC inputs as digital input bits or
    digital input interrupt bits or something like that.

    The comparator circuit isn't especially complex, you
    could buy a comparator that runs on either +5V or
    +3.3V or +2.5V or whatever matched your PIC
    power supply and logic levels, and you could get the
    comparators 4 comparators per DIP package of
    14 or 16 pins. You'd need two resistors for hysteresis
    on each comparator, and the quad-comparator IC
    would have enough comparators for one for each of your
    four solar cell inputs. It would be about as simple
    and low cost as you are going to get for a solution
    to a threshold detection comparator problem.

    However, again, that doesn't seem to be necessary
    if you intend to use the PIC inputs as ADC inputs and just
    select some digitized signal level X as your decision
    threshold in software.

    To prevent ESD or over-voltages from the cell inputs
    from damaging the PIC, you could put these diodes
    on each sensor input:
    1) diode cathode to solar cell; diode anode to ground
    2) diode anode to solar cell; diode cathode to +Pwr supply

    1n914 diodes or any small signal switching diode
    or general purpose small signal schottky diode would be

    Double check what you have your feference voltage
    for ADC conversion set to be, and the PIC power supply
    voltage ; you could get erroneous operations if your
    signal voltage (e.g. +2.5 to +5Vdc) range appearing
    at the PIC exceeded either the PIC's power supply
    voltage, or if it exceeded the maximum postiive input
    voltage that the ADC can accept to give positive
    full scale readings given the selected modes/reference.

    I assume the negative end of the solar cells is grounded
    to the PIC's analog & digital ground, and that the
    solar cell polarities are hooked up to give only
    positive voltages to the PIC inputs, so you shouldn't
    have signal excursions more negative than the PIC
    power supply unless the PIC was powered down
    (which the diodes I mentioned would help solve),
    though you could still exceed the most negative
    ADC input common mode input voltage that corresponds
    to a digitized 000 if that happens at a voltage much
    above 0V in the PIC's ADC/reference range.
  6. Jul 18, 2007 #5


    User Avatar

    Re: quad comparators:
    http://www.national.com/mpf/LM/LM339.html [Broken]

    The National (or equivalent) LM139/LM239/LM339
    is a quad comparator that can be powered
    anywhere from +2 to +36Vdc, and is available in
    a 14 pin DIP package.

    You would use a pull-up resistor on its output going to
    your system's positive logic supply voltage, since the
    comparator happens to be an open-drain part.

    Three additional resistors would yield a hysteresis
    function that would allow a cleaner jitter-free
    digital output from an analog input that is
    potentially fluctuating near the comparator threshold.

    A simple two-resistor voltage divider
    between (analog positive power supply) and
    (analog ground) would yield a mid-point reference
    voltage that could be fed to all of the 4 comparators'
    reference inputs to determine your comparator switching
    point thresholds. If you had an output (e.g. 2.5V)
    Vref from the PIC or elsewhere, of course you could use
    that as +Vref for each of the comparators instead.

    For hysteresis

    resistor-A would go from the solar cell
    output to the (+) comparator input.

    resistor-B would go from the comparator output to
    the (+) comparator input.

    resistor-C would go from the
    (+) comparator input to analog ground


    The comparator output transitions aren't as fast
    as some other digital logic, but they're probably
    acceptably fast for PIC digital inputs; check the
    datasheet parameters for max. input rise/fall time for
    the PIC vs. the comparator output rise/fall time given
    a certain pull-up resistor on the open drain output.
    Last edited by a moderator: May 3, 2017
  7. Jul 19, 2007 #6
    "You mean the capacitors have one end grounded and the
    other end tied to the solar cell output?"

    Yes, you're right. I meant to say that the capacitors were in parallel with one end connected to the solar cell and the other end grounded.

    "What's the power supply voltage of the PIC?"
    What's the specified input voltage range of the PIC ADC
    based on your power supply and reference voltage

    The power supply voltage for the PIC is 5V.The ADC has a Vref+ which is connected to the same 5V as the PIC and a Vref- which is connected to ground (the same as that of the PIC)

    "Since you said the lighted voltage of the solar cells
    is 2.5-5V, I assume that means that the PIC analog
    input can handle such voltages."


    "you could just use two-resistor a resistive voltage divider
    to attenuate the input voltages by some multiplier e.g
    0.5x or 0.7x or whatever. Connect a 4.7k resistor to
    the solar cell, and a 22k pot to ground"

    So the solar cell's positive input connects to the 47k resistor which connects to the 22k pot which in turn goes to ground.The pot's wiper then goes to the PIC analog input.Did I understand correctly?

    I'm not sure I understand how to attenuate the input voltage by a multiplier as you mentioned (0.5x or 0.7x).Is that by the voltage divider rule? And what does the 'x' in the 0.5x stand for?
    How can I find out exactly by what fraction I attenuated the signal?

    "I assume the negative end of the solar cells is grounded
    to the PIC's analog & digital ground, and that the
    solar cell polarities are hooked up to give only
    positive voltages to the PIC inputs"

    Yes, the negative end of the solar cell is grounded (it's the same ground as the PIC's).The positive end of the solar cell is connected to the PIC analog input.No, I did not get a negative voltage at the solar cell's postive input when I connected a multimeter across it.

    I think I'll opt for the 47k resistor and 22k pot voltage divider circuit since the Schmitt trigger and comparator circuits deal with digital outputs and I have my PIC inputs configured as analog ones.

    So the voltage at the 22k pot's wiper would be about 2.1V (going into the PIC analog input) if the voltage at the solar cell is 2.5V (according to the voltage divider rule).I think that works! If I need to trigger the solar cells at a voltage higher than 2.5V I could use a bigger resistance in place of the 4.7k fixed resistor.

  8. Jul 19, 2007 #7
    I've done something like this before. Implement hysteresis with your uC!
  9. Jul 19, 2007 #8


    User Avatar

    If you have a network as follows:

    S = signal voltage, i.e. connected to the positive output
    of your solar cell.

    O = Attenuated output voltage going to your PIC ADC

    GROUND = Where the PIC power supply, -Vref,
    and Solar cell negative side are grounded to.

    R1 = Resistor
    R2 = Resistor

    You have:

    I = current through the resistors = S/(R1+R2)
    O = voltage at PIC ADC in = (I * R2)
    so combining:
    O = (S * R2 / (R1+R2))

    So R2/(R1+R2) is a multiplicative attenuating factor
    that divides the input voltage, or, rather, multiplies it
    by that fractional value that is less than or equal to 1.

    So if
    R1=000k Factor = (100k)/(100k+000k)=1.0
    R1=001k Factor = (100k)/(100k+001k)=0.99
    R1=010k Factor = (100k)/(100k+010k)=0.90
    R1=030k Factor = (100k)/(100k+030k)=0.769
    R1=100k Factor = (100k)/(100k+100k)=0.500
    R1=200k Factor = (100k)/(100k+200k)=0.333
    R1=470k Factor = (100k)/(100k+470k)=0.175

    So you could make either R1 or R2 a pot hooked up as a variable
    resistor and get an easily variable range of attenuations within
    the limits that you'd calculate by the above voltage divider equation
    and the limits of your pot (0k to whatever).

    If you wanted you could *just* use a single pot since
    then you'd have a three terminal device:
    where R1 and R2 were actually the same resistor and 'O' being
    connected to the 'wiper' terminal of the pot would move anywhere
    along the resistance spread of the pot thus creating
    two resistors one being from the wiper to one end of the pot,
    the other being from the wiper to the other end of the pot.
    In this case you'd have the (O) signal taken from the wiper
    being anywhere from 100% of the input signal to 0% of the input

    Your PIC chip's ADC input pin probably has some "built in"
    resistance (ADC input resistance or input impedance on the data sheet))
    to ground, though, so it'll act as if there's a smaller value of R2
    than you really have in the circuit because of that.

    Similarly the solar cells have some output impedance that
    depends on the light level and the solar cell etc. that looks
    like a 'R1' resistor of some value built into the solar cell,
    so because of that the circuit will perform as if R1 is bigger
    than it really is.

    To deal with those effects you want to use some compromise
    value of R1 and R2 so that you're not presenting too low of
    a total resistance on the solar cell while yet not presenting
    too high of a total resistance to the PIC ADC input.

    Thus you'd probably use some limit like
    (R1+R2) = somewhere in the range of 10k to 47k combined and
    then your divider operation should be fairly predictably correct
    despite the actual internal resistances in the solar cell and PIC chip
    because of the kinds of values experience teaches me that they're likely
    to be. It's a relevant concern if you need to know to high accuracy
    precisely *what* the attenuating factor is, but if you just need
    a relative "ballpark estimate" of an attenuation factor X then
    just hook it up with convenient values and it'll work fairly close
    to the predicted values.
  10. Jul 19, 2007 #9
    "Your PIC chip's ADC input pin probably has some "built in"
    resistance (ADC input resistance or input impedance on the data sheet)"

    Yes the maximum input impedance is 2.5k

    Thanks for your reply!

    I think I'll use the first two resistor voltage divider configuration you suggested.


    I had a 0.1uF capacitor in parallel with the solar cell, should I leave it connected between signal<O> going into the PIC or no?
    I also had another idea that I'd like to ask you about.I'm not sure if it'll work or not but here goes..

    <S>--<Scmitt trigger IC>---<R1>---<base of NPN transistor>
    <emitter of NPN>--ground
    <S>--<R2>--<collector of NPN>--<PIC analog input>

    I'm not sure what value to pick for R2 but R1 could be=(Vcc-Vbe)/Ibase; Vbe~0.7V, Ibase-->from the spec sheet of 2n3904(those are the ones I have handy).
    The schmitt trigger IC would be powered by Vcc as V+ and ground as V-.
    The <S> would be the signal from the solar cell or Vref and that same signal goes
    into the collector of the NPN transistor through a high resistance R2.

    The way I understand it,when Vref would be greater than 2.5V there would be a low signal at the output of the schmitt trigger which would cause the NPN transistor to stay off and so the Vref going into the PIC would be high.If Vref is less than 2.5V there would be a high signal at the output of schmitt trigger IC which would turn the NPN transistor on and cause a drain at the collector so the PIC would receive a low voltage.

    Do you think this arrangement might work?If it does I might try it this way as well.Could you please recommend
    a Schmitt trigger IC I could use for this application.

    Thanks for your suggestions!

  11. Jul 19, 2007 #10


    User Avatar
    Staff Emeritus
    Science Advisor
    Gold Member

    You could also simply purchase an ambient light sensor with an integrated digital serial interface, like the ISL29001 from Intersil. It would probably be a snap to implement.

    - Warren
  12. Jul 19, 2007 #11
    Thanks Warren!
  13. Jul 22, 2007 #12

    I tried to use the voltage divider approach with a 5K pot. But at the output of the voltage divider ( analog input to the PIC) the voltage is very low like about 5mV. This is the way I connected it-->

    <positive end of Solar Cell>--><one end of 5K pot>
    <other end of pot>--><Gnd><--<negative end of Solar Cell>
    <wiper of pot>--> <PIC analog input>

    I'm not sure why this is happening.I'd appreciate any suggestions or advice.

    Thanks in advance,
  14. Jul 22, 2007 #13


    User Avatar
    Science Advisor
    Gold Member

    I just looked at the "www.clare.com/home/pdfs.nsf/www/CPC1822.pdf/$file/CPC1822.pdf"[/URL] The short circuit current under direct sunlight (6000lux) is only 50 uA. Try a higher resistance pot.
    Last edited by a moderator: Apr 22, 2017
  15. Jul 22, 2007 #14
    Thanks dlgoff!

    I used a 20k pot in series with a 8.2k resistor. I get the desired result (without using the solar cell) when I use Vcc (5V)to one end of the 8.2k resistor .But when I connect the solar cell and shine a light on it ( the voltage which should increase to about 3V-4V) changes very little above 0V.I tried to measure the current through the circuit .I get a reading of 0.12A and then it decreases to less than 50uA (the short circuit current of the solar cell).I'm not sure why this happens when I use the solar cell.

    How can I go about solving this problem?

  16. Jul 23, 2007 #15


    User Avatar

    "I had a 0.1uF capacitor in parallel with the solar cell, should I leave it connected between signal<O> going into the PIC or no?"

    Leave it connected across the solar cell terminals
    themselves and it'll be fine. If you really end up with
    a serious problem of the analog signal changing too
    rapidly or getting high frequency noise coupled into your
    circuit then you could look at more intensive
    capacitive+resistive filtering connections.
    But for the moment that doesn't seem to be a problem and
    leaving it across the solar cell terminals is just fine for
    just a little bit of filtration.

    A good schmitt trigger for use between +5V
    power supply and 0V ground logic would be the
    74HC14, I'd guess that you could get them cheaply
    in quantity one from DigiKey, Mouser, Newark, et. al.,
    and that the datasheets would be available from
    www.ti.com[/url], [url]www.fairchild.com[/URL], etc.
    They are INVERTING S.T. gates, though, FYI, so use
    two in series or just realize/accept the signal inversion.

    R1 being between a CMOS +5V logic schmitt trigger
    output and the base of an NPN transistor whose emitter
    is grounded would be having about +5V across it when
    the S.T. output is HIGH.
    The S.T. can drive 10 TTL load equivalents, and is
    specified with the absolute maximum current output per
    pin of 25mA. So choosing 3mA of base current to the
    transistor should be a reasonable compromise. As you
    said, V_BE is around 0.7V for a typical single small
    signal NPN, so 5-0.7 = 4.3V, and so about 1.5k R1 would
    give you about 3mA of base current when the S.T. is high.

    As for the rest:
    <S>--<R2>--<collector of NPN>--<PIC analog input>
    <+VREF>--<R2>--<collector of NPN>--<PIC analog input>
    <+5V>--<R2>--<collector of NPN>--<PIC analog input>

    Well I don't see too much point in any of the options there
    but your logic with the transistor operation is mostly

    If the S.T. output is low, the transistor will have
    I_BASE = 0, the NPN will be OFF / non-conducting, and
    there will be basically a high resistance between
    emitter and collector. Since the collector goes to the
    PIC input, the PIC will effectively see a signal input
    equal to whatever is connected to the PIC input
    ignoring the transistor which acts like an open circuit
    between its C and E when it's OFF. If you had
    <S>--<R2>---<PIC INPUT> where <S> is the
    solar cell, it'd be the same as having the solar cell go
    to the PIC IN through R2 when the transistor is OFF.

    If you have <+5V>---<R2>---<PIC INPUT> then
    when the transistor is OFF the PIC would see
    +5V through R2 resistance on its input.
    The similar would be true if the source was <VREF>
    assuming <VREF> is some fixed positive voltage
    between +2.5 and +5VDC.

    When the S.T. output is HIGH, transistor base gets 3mA
    current, the collector emitter path goes to some fairly
    low resistance, and assuming R2 is more than a few
    hundred ohms, the collector voltage would be getting
    down into the range of less than +0.5VDC so the PIC
    would see a low voltage signal.

    However if what you want is a LOGIC level
    at the PIC input, why not just reconfigure the PIC
    input as a LOGIC input and not an ADC analog input.

    Then you could just do:
    <+SOLAR CELL>---<ST IN>

    and you have a logic input to the PIC that is
    0 if the solar cell terminal goes from dark low voltage
    to illuminated higher voltage and transitions to
    output somwhere between +2.3 and +3.1VDC.

    1 when the solar cell was illuminated but goes dark
    and transitions from a high positive voltage output
    lessening to somewhere between +2.0 and +0.9VDC.

    If you want that inverted logically you could just connect
    another ST gate in series with the first
    and then have the opposite
    <1> <0> sense of those logic levels appearing at the PIC.

    If you really wanted the solar cell analog voltage to appear
    at the PIC ADC analog input, I don't see too much point
    in adding the S.T. and NPN...

    Now if you wanted you could tie the solar cell analog
    to the PIC ADC, AND tie the solar cell analog to some
    S.T. type of circuit whose logic output goes to some
    DIFFERENT PIC logic interrupt input pin configured to
    give you an software interrupt when there is a logic level
    change based on the solar cell voltage so your
    software could go out and measure the actual voltage
    of the ADC at that moment or something.

    But if you want to work with analog signals and you
    had something like an 8 bit ADC with
    +VREF = +VIN_MAX = +5V, then
    ADC 255 = +5.00VDC in
    ADC 127 = +2.50VDC in
    ADC 063 = +1.25VDC in
    etc. so you can just choose some number of ADC
    reading as a threshold for saying "light" or "dark"
    and then it is a small matter of choosing whatever
    ADC number best suits the light level you're trying to
    detect. It shouldn't be very necessary to use
    external comparators, schmitt triggers, attenuators,
    amplifiers, etc. to make the level of the signal that
    corresponds to 'light' and 'dark' some particular value
    since the ADC in the PIC can already (with some
    limited resolution) tell you the value anywhere between
    +VREF and 0V.
    Last edited by a moderator: Apr 22, 2017
  17. Jul 23, 2007 #16


    User Avatar

    My guess is that maybe you've mixed up the
    wiper of the POT and the fixed end-terminals of
    the POT. There is no fixed mode of construction to
    tell which terminal is which, so unless you have the
    data sheet or a diagram/label on the pot itself, or have
    measured it with a ohm meter to distinguish the
    terminals, room for confusion exists.

    I am surprised the PIC has such low input impedance,
    usually ADCs are more than ~ 2.5k to ~ 6k ohms
    input resistance or input impedance for general purpose
    usages at low frequencies. Anyway since you use a 5K
    pot there will be an action as if the lower resistor in
    the pot was lower than it is e.g. the parallel combination
    of the lower resistor with the PIC ADC input resistance
    to ground.

    But that would not be such a severe effect as to make
    the PIC measure only 5mV of signal even when the
    solar cell puts out a signal that would be read as more
    than +2.5V if you had not used the POT as a
    voltage divider.

    Consequently there may be a defect in wiring or
    misidentification of the POT terminals etc.

    You could use a lower impedance POT of 2K or 1K if
    you wanted more accuracy of voltage division compared
    to the low input impedance of the PIC ADC, but even
    a 5K pot should give you very suitably adjustable
    voltage inputs to the PIC, so there must be an error
    in wiring or in the programming of the PIC.

    Use a DMM. Adjust the pot wiper in the middle of
    the range of motion. Measure between
    <A> to <B> and <A> to <C> and <B> to <C>.

    Whichever one of those measurements yields close to
    5K ohms for a 5K pot and such that the measurement
    does NOT change when you change the position of the
    pot wiper, those are your pot's fixed terminals.
    The other pin is the wiper.

    Set the DMM on DC voltage measurement mode
    with the probes set to measure in the range of
    0V to +20V or so. Or +12V or +10V range, whatever.
    If you connect +5VDC to one pot end terminal and GND
    to the other pot end terminal you should be
    able to measure anywhere from +5VDC down to 0Vdc
    voltage on the wiper pin relative to GND pin depending on
    your adjustment of the wiper from one extreme to
    the other. It should not matter much if the PIC
    ADC input is also connected to the wiper or not when
    you perform such measurement.

    Make sure the PIC has power applied, though, and
    consider using proper techniques to prevent
    electrostatic discharge and handling related
    voltage and current / mechanical disruptions to the PIC
    as you work on the circuitry while the PIC is connected.

    Also consider adding the diodes I mentioned
    between PIC ADC IN and GND and +PIC POWER SUPPLY
    to protect the PIC from voltages/currents that can appear
    on its ADC input. It's conceivable that the PIC's
    ADC input could get "locked up" temporarily
    into some strange mode where it has low resistance to
    ground, even much moreso than normal, if it has had
    a voltage at its input that isn't proper for it.

  18. Jul 23, 2007 #17


    User Avatar

    Oops! Being a "solar cell" I assumed it had a typically
    LOW output impedance that'd be useful if it was to
    be providing power to other electronics.

    50uA in the bright light indicates a very high
    output impedance solar cell that is really more of a
    "light sensor" than a "photovoltaic power cell".

    You have a bit of a problem here because the PIC has
    a LOW ADC input resistance of ~ 6 kOhms.
    And the best suited output impedance to drive the PIC
    ADC input is between 0 and 5kOhms, the less the better.

    The solar cell, on the other hand seems to be a high
    impedance sensor with a few kilo ohms of internal

    Choosing a pot that's high impedance to act as a precise
    voltage divider that doesn't load the solar cell too much
    would indicate pot resistances in the 10's of kilo-ohms.
    But that'd be unsuitable since the PIC's
    low input impedance would drastically load the
    voltage divider.

    What you might consider doing is using a 10k variable
    resistor (pot wiper to one pot end terminal, leave the other
    pot terminal disconnected) between the PIC & S.C.
    <SOLAR CELL+OUT>---<R1>---<PIC ADC IN>

    Then there will be some voltage dropped by the input
    current of the PIC and you'll see a bit of attenuation,
    though it might depend on how often you read the ADC.

    I guess there's no harm in trying a higher 20K or so
    R1,R2 divider... maybe you have.. Let's see...
  19. Jul 23, 2007 #18


    User Avatar

    I am confused. It sounded like the problem at first
    was that the solar cells were *too* sensitive and
    output *too much* voltage for you. Now they seem as if
    they're a bit feeble in their output.

    You could connect a parallel resistance with the solar
    cell to give it a resistive load even less than the PIC's
    ADC impedance, that'd attenuate the signal read
    by the PIC because part of the voltage would drop across
    the internal series output impedance of the solar cell.

    <PIC ADC IN>----<+SC>----<R1>---<GND>

    R1 could be the wiper and one end terminal of a 50k pot
    hooked up as a variable resistor.

    I am pretty sure you'd end up with some satisfactory
    load resistance setting that would yield an
    sufficiently attenuated but sufficiently strong signal
    going in to the PIC.

    I am still confused that your PIC ADC just hooked to the
    naked <+SOLAR CELL> output doesn't just give you a
    digital reading of 0...N corresponding to 0...+5V and
    among those values, one of them would be a suitable
    threshold for your light / dark decision point.

  20. Jul 23, 2007 #19


    User Avatar
    Science Advisor
    Gold Member

    "I'm not sure why this happens when I use the solar cell."

    What type of light source are you using? Have you tried it in sun light?
  21. Jul 23, 2007 #20


    User Avatar

    That's likely because
    a) there's a capacitor in parallel with the solar cell,
    so the capacitor charges slowly from the solar cell, but
    when discharged the capacitor can provide a high burst
    of current that gradually tapers down until at a long time
    short circuit you just get the continuous stream of
    current at the rate the solar cell can supply into a short.


    b) because voltmeters / ammeters often have some
    time of instability / fluctuating readings as they
    begin to track a new signal, the signal changes, etc. and
    eventually the readings settle down. Sometimes it's due
    to genuine changes in the signal being measured (e.g.
    the charge or dischargs of a capacitor), other times it's
    just the way the meter does its ranging and estimation,
    often times being confused by waveforms that may not
    be sine-waves in the case of AC circuits.
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Similar Discussions: Light sensor
  1. Light sensor help (Replies: 0)

  2. What is this sensor? (Replies: 1)