Hi,(adsbygoogle = window.adsbygoogle || []).push({});

I am trying to prove algebraically that light cannot pass across the corner of a right-angled block of glass of refractive index n=1.5. Would someone be willing to let me know whether the method I have used below is valid or not?

'i1' denotes the angle of incidence that the light ray makes with the corner of the glass on entry, 'r1' its angle of refraction. 'i2' denotes the angle of incidence the light within the glass makes against the side perpendicular to the side of its entry, and 'r2' denotes the angle of refraction.

If the light ray is to escape, r2 < 90.

Now n = (sin i1)/(sin r1) ... [1]

And (1/n) = (sin i2)/(sin r2) ... [2]

Since i2 is simply made by the refracted ray with the normal of the perpendicular side,

i2 = 90 - r1.

Therefore sin i2 = cos r1.

From [2], sin r1 = sin i1 / n

From [1], cos r1 = sin r2 / n

Given that sin^2 r1 + cos^2 r1 = 1

(sin r2)^2/n^2 + (sin i1)^2/n^2 = 1

Therefore

sin r2 = sqr(n^2 - (sin i1)^2)

But there are no values of i1 (the angle of incidence) such that 0 <= sin r2 < 1 therefore no value of i1 will produce an angle such that 0 <= r < 90.

Not an elegant proof, perhaps, but is it valid? Anyone care to suggest a better one (just using algebra)?

Cheers.

**Physics Forums | Science Articles, Homework Help, Discussion**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Homework Help: Light through the corner of a glass block

**Physics Forums | Science Articles, Homework Help, Discussion**