I've been given this question by a teacher and I'm clueless as to what b) and c) are. Could you please help? I would really appreciate it. The prize is a place to see a lecture on quantum simulation at our local University.
Thank you :)
Welcome to the PF.I'm still lost on hysteresis. For c) I would suppose the gradient denotes the resistance, because I =V/R
No, we assume that you are the kind of person who wants to know how to GET answers and learn things. That's the thrust of this forum, to promote learning, not to give answers. I understand that you HAVE the answer and so are not looking for that, but I'm trying to address the sentence that I just quoted.You assume I'm one of those people who wants the answer all laid out, well I'm not
That's an excellent understanding of hysteresis and is correct for this problem.My current answer to B would be:
The increase in the filament's temperature also increases the resistance of the filament and a greater change in voltage is required to cause a change in the current. The shallower gradient shows this. When the bulb is decreased, the slope was lower for the turning off than the initial part of turning on. This is because the filament has not had enough time to cool down, and the resistance is still high due to the heat. This causes the smaller gradient for the second line.
But it does.But I don't think this answers the question.
Odd since you just did a great job of stating how it DOES relate to the matter at hand.Hysteresis is the time delay between the effect and the cause of a system, the effect being a value of Ia physical property such as magnetic induction, caused by an electromagnet. I honestly have no idea how this relates to the matter at hand.
Hm ... Do you not see two curves in the hand drawn graph? The lower one is as the voltage went up, heating the filament and the upper one is as the voltage is then lowered but with the filiment already hot, just as you described it above.EDIT: I don't see how the graph in the question shows a hysteresis curve either, maybe that's the root of the problem
The lower one is as the voltage went up, heating the filament and the upper one is as the voltage is then lowered but with the filiment already hot, just as you described it above.