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computerex
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Can someone confirm the solution? My elder sister who is in college had this problem for homework, and asked me weather I could take a look at it. For some reason however my answers are incorrect, and I was wondering weather anyone could point me in the correct direction.
a. A person witnesses a lightning strike pass near an airplane. Approximately 5.1 seconds after the lightning strike, the person hears the thunder. The airplane passes overhead 11 seconds following the lightning strike. Assuming the speed of sound to be 1100 ft/s, what is the distance of the person from the airplane precisely when the lightning strikes?
b. What is the average speed the plane is traveling at?
average speed = distance/time
distance = time * average speed
The distance from the person to the lightning strike can be found by:
d = 1100*5.1
= 5610
For simplification, assuming that the distance of the airplane from the person is equivalent
to the distance of the lightning strike from the person, the distance of the airplane from the person is approximately 5, 610 ft.
The solution to the second part of the problem can be found by dividing 5610, the distance of the airplane from the person, by 11, the time it takes for the airplane to reach the person, giving you an average speed of 510 ft/s.
Homework Statement
a. A person witnesses a lightning strike pass near an airplane. Approximately 5.1 seconds after the lightning strike, the person hears the thunder. The airplane passes overhead 11 seconds following the lightning strike. Assuming the speed of sound to be 1100 ft/s, what is the distance of the person from the airplane precisely when the lightning strikes?
b. What is the average speed the plane is traveling at?
Homework Equations
average speed = distance/time
distance = time * average speed
The Attempt at a Solution
The distance from the person to the lightning strike can be found by:
d = 1100*5.1
= 5610
For simplification, assuming that the distance of the airplane from the person is equivalent
to the distance of the lightning strike from the person, the distance of the airplane from the person is approximately 5, 610 ft.
The solution to the second part of the problem can be found by dividing 5610, the distance of the airplane from the person, by 11, the time it takes for the airplane to reach the person, giving you an average speed of 510 ft/s.