- #1
PhizKid
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Homework Statement
[tex]\lim_{x \to \infty } \frac{\sin x}{x}[/tex]
Homework Equations
The Attempt at a Solution
[tex]\lim_{x \to \infty } \frac{\sin x}{x}[/tex]
Substitute x = 1/u
[tex]\lim_{\frac{1}{u} \to 0 } \frac{\sin \frac{1}{u}}{\frac{1}{u}} = 1[/tex]
I know this is incorrect because intuitively I know that sinx will oscillate between 0 and 1, but the denominator will grow larger infinitely, therefore should theoretically approach 0 but that's just my thinking and no hard evidence.