- #1

- 590

- 0

Lim

_{x->infinity}x*((x

^{3}+x

^{2}+ax)

^{(1/3)}-(x

^{3}-bx)

^{(1/3)}) = 3

what i thought was

t=1/x

Lim

_{t->0}1/t*((1/t

^{3}+1/t

^{2}+a/t)

^{(1/3)}-(1/t

^{3}-b/t)

^{(1/3)}) = 3

Lim

_{t->0}1/t*((1/t

^{3}+1/t

^{2}+a/t)

^{(1/3)}-(1/t

^{3}-b/t)

^{(1/3)}) = 3

since here we have 0/0 i can use l'hopital's law, but it looks like its going to get really ugly whith too manu terms,

also how can i solve for both A and B when i have only one equation