- #1
Bohrok
- 867
- 0
[tex]\lim_{x\rightarrow 0} \frac{\sin^3x}{\sin x - x}[/tex]
I've been trying to find this limit the hard way without l'Hôpital's rule, but no luck. I've tried different things like factoring the difference of cubes to get rid of the denominator, but I can't get out of an indeterminate form. I did get sin3x/(sinx + x) but that didn't help. that x by itself seems to be causing the problem. This one's got me a little frustrated but I must be missing something relatively simple...
I've been trying to find this limit the hard way without l'Hôpital's rule, but no luck. I've tried different things like factoring the difference of cubes to get rid of the denominator, but I can't get out of an indeterminate form. I did get sin3x/(sinx + x) but that didn't help. that x by itself seems to be causing the problem. This one's got me a little frustrated but I must be missing something relatively simple...